If α and ß are zeros of x ²-x +4 , then find
i) α+ß
ii) αß
iii) 1/α + 1/ß- αß
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Answer:-
Given:
α and β are the roots of x² - x + 4.
Let a = 1 , b = - 1 , c = 4.
We know that,
Sum of the zeroes = - b/a
→ α + β = - ( - 1) / 1
i) α + β = 1 -- equation (1)
Product of the zeroes = c/a
→ αβ = 4/1
ii) αβ = 4 -- equation (2)
iii) 1/α + 1/β - αβ
Taking LCM we get,
→ [ α + β - (αβ)(αβ) ] / αβ
Putting the values of α + β and αβ from equations (1) & (2) we get,
→ [ 1 - 4 * 4 ] / 4
→ [ 1 - 16 ] / 4
→ - 15/4
Hence,
- α + β = 1
- αβ = 4
- 1/α + 1/β - αβ = - 15/4.
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