Math, asked by Bhanupartap2954, 4 months ago

Ifαandβaretherootsofx2+7x+10=0findthevaluesofi)α2
β
+β2
α
ii)α2+β

Answers

Answered by ishanshidivakar5a
0

Answer:

ANSWER

Given: f(x)=3x

2

−7x−6

Which is of the from ax

2

+bx+c

⇒a=3,b=−7,c=−6

Now, α+β=−

a

b

=

3

−(−7)

α+β=

3

7

....(1)

and αβ=

a

c

=

3

−6

αβ=−2...(2)

(1) α

2

2

=(α+β)

2

−2α+β

=(

3

7

)

2

−2(−2) [ from (1) & (2)]$$

=

9

49

+4=

9

49+36

=

9

85

α

2

β

2

=(αβ)

2

=(−2)

2

=4

The pohynomical whose roots are α

2

2

is given by , x

2

−(sumofroots)x+productofroots

=x

2

9

85x

+4

=

9

9x

2

−85x+36

=

9

1

(9x

2

−85x+36)

(2) (2α+3β)+(3α+2β)=5α+5β

=5(α+β)

=5⋅

3

7

=

3

35

(2α+3β)+(3α+2β)=6α

2

4αβ+9αβ+6β

2

=6(α

2

2

)+13αβ

=6{(α+β)

2

−2αβ}+Bαβ

=6(α+β)

2

−12αβ+Bαβ

=6(α+β)

2

+αβ

=6(

3

7

)

2

+(−2)

=6⋅

9

49

−2

=

3

98

−2

=

3

98−6

=

3

92

the required polynomial whose you are (2α+3β) and (3α+2β) is

x

2

3

35

x+

3

92

=

3

1

(3x

2

−35x+92)

Answered By

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