If and b are the roots of x^2-7x +12 then the equation whose roots are 3a and 3b
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Step-by-step explanation:x^2-7x+12
x={7±√(49-48)}/2
x=4,3 are the roots
a=4,b=3
3a+3b=12+9=21
3a.3b=12.9=108
x^2-Sx+P=0
x^2-21x+108=0
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