If and b are the zeroes of the polynomial x2_6x+k, find the value of k, such that a2+b2=40
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sum of zeros= -b/a = 6/1
product of zeros= c/a = k/1
(a+b)^2 = a^2 + 2ab + b^2
a^2 + b^2 = (a+b)^2 -2ab
= 6^2 -2k
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Answer: -2
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