If α and β be the zeroes of the polynomial x^2 + 4x + 3, find the quadratic polynomial whose zeroes are 1+α/β and 1+β/α
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Answer:
Step-by-step explanation:
p(x)= x^2 + 4x + 3
now factorise,
x^2 + 3x+ 1x + 3
x( x + 3 ) + 1( x+ 3)
(x+1) (x+3)
thus, x = -3 and x = -1
thus, α = -3 β = -1
find the quadratic polynomial whose zeroes are
1+α/β and 1+β/α
1+-3/-1 and 1+-1/-3 (substituting the values)
1+3/1 and -1+-1/3
4 and 0/3
4 and 0
thus the Zeros of new equation are 2 and 0
Sum =
0 + 2 = 2
Product =
0 × 2 = 0
using the formula to form a quadratic polynomial
x^2 - (sum of zeroes)x + product of zeroes
sunstituting values
x^2 - 2x + 0
i.e
Ans, x^2 - 2x
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