If α and β αre zeros of Quadratic polynomial p(x) = x² +10x+25 Find the value of (α+β)/αβ.
Answers
Answer :
The value of (α + β)/αβ is -2/5
Step-by-step explanation :
➤ Quadratic Polynomials :
✯ It is a polynomial of degree 2
✯ General form :
ax² + bx + c = 0
✯ Determinant, D = b² - 4ac
✯ Based on the value of Determinant, we can define the nature of roots.
D > 0 ; real and unequal roots
D = 0 ; real and equal roots
D < 0 ; no real roots i.e., imaginary
✯ Relationship between zeroes and coefficients :
✩ Sum of zeroes = -b/a
✩ Product of zeroes = c/a
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Given quadratic polynomial,
p(x) = x² + 10x + 25
It is of the form ax² + bx + c
a = 1 , b = 10 , c = 25
⇒ Sum of zeroes = -b/a
α + β = -10/1
α + β = -10
⇒ Product of zeroes = c/a
αβ = 25/1
αβ = 25
(α + β)/αβ = ?
(α + β)/αβ = -10/25
(α + β)/αβ = -2/5
The value of (α + β)/αβ is -2/5