If and term of an ap is 2 x + 1 then find the sum of first n terms of the AP
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Step-by-step explanation:
an=(2n−1)
⇒ a1=2×1−1=1
⇒ a2=2×2−1
=4−1
=3
⇒ d=a1−a1=3−1
∴ d=2
⇒ S1=2n[2a1+(n−1)d]
=2n[2(1)+(n−1)2]
=2n[2+2n−2]
=2n×2n
=n2
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