If ∝ and U are zero’s of the quadratic polynomial p(x) = 2x2− 5x + 7 find a
polynomial whose zeros ae 2∝ +3 U and 3∝ + 2 U
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Answer:
2x²-25x+82 is the required polynomial
Step-by-step explanation:
Let the zeros of given polynomial be @ and ß
p(x)=2x²-5x+7
Here,we obtain:
@+ß=5/2 and @ß=7/2
Let S and P be the sum and product of zeros of required polynomial respectively.
Given that 2@+3ß and 3@+2ß are the zeros.
Now,
S=(2@+3ß)+(3@+2ß)
=5@+5ß
=5(@+ß)
=5×5/2
=25/2
P=(2@+3ß)(3@+2ß)
=6@²+4@ß+9@ß+6ß²
=6@²+13@ß+6ß²
=(6@²+12@ß+6ß²)+@ß
=6(@²+2@ß+ß²)+@ß
=6(@+ß)²+@ß
=6×(5/2)²+7/2
=6×25/4+7/2
=150/4+7/2
=(150+14)/4
=164/4
=82/2
➡️Required polynomial:
x²-Sx+P
=x²-25/2x+82/2
Multiplying the whole equation by 2
=2x²-25x+82
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