Question

If angle a=30° then prove that 1 tan^2 A = sec^2 A

Answer 1

proved

Step-by-step explanation:

A=30°

NOW,

tan(2*30°) = tan 60°

= = tan 60° = v3

tan/(1 - tan?A)

= = 2tan30/(1 - tan²30°)

= (2*1/03) / (1 - 1/3)

= 2/V3/ (3 - 1)/3 =

= 2/V3/2/3 =

= = 2/V3 * 3/2

= v3

Answer 2

Answer:

Step-by-step expla

When A=30°

or,1+tan^2A=Sec^A

or,1+tan^2(30)=sec^2(30)

1+(1/$\sqrt{3}$ )^2=(2/$\sqrt{3}$ )^2

1+1/3=4/3

4/3 =4/3

LHS=RHS

proved