If angle A & angle B are acute angle such that cosA=cosB ,then show that angle A = angle B
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Answered by
23
take this as the figure...
cos A = cos B
ie. AC/AB = BC/AB
this implies AC = BC
so by isosceles triangle property
angle A = angle B
.
.
.
hope this helps uh!!!
cos A = cos B
ie. AC/AB = BC/AB
this implies AC = BC
so by isosceles triangle property
angle A = angle B
.
.
.
hope this helps uh!!!
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Answered by
6
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