if angle A and angle B are acute angle such that CosA= CosB ,then show that angle A= angle B .
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Cos A = cos B.
cos a = b1/h1
cos b = b2/h2
so b1/h1 = b2/h2
=>b1/b2 = h 1/ h2
since sides are proportional so triangles are proportional
so angle a = angle b
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