If angle A and angle B are acute angles such that cosA =cosB , then show that angle A = angle B.......
please don't write anything useless if you don't know the answer
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ln right angled triangle ABC right angled at C
CosA=CosB
AC/AB=BC/AB
AC=BC
•°• <A=<B
(angles opposite to equal sides are equal)
HENCE PROVED
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