Question

if angle a and angle b are acute angles such that cosA=cosB, then show that
angleA=angleB.



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solve this problem by using obe triangle only
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Answer 1

Answer:

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if angle a and angle b are acute angles such that cosA=cosB, then show that

angleA=angleB.

$\huge\color {Pink}\boxed{\colorbox{black}{ \ Answer♡}}$

Given :

According to the question:-

Let cosA= Hypotenuse sideadjacent A AB AC

Similarly, cosB= Hypotenuse sideadjacent B = AB BC

To find :

Given that

cosA=cosB

AB AC = AB BC

Solution :

AC=BC In triangle,

angles opposite equal side are equal

∠B=∠A

Step by step explanation :

If ∠A and ∠B are acute angles such that cosA=cosB , show that ∠A=∠B.

Hint: In general opposite angles of equal sides are also equal.

We can prove angle A equal to angle B by proving opposite sides of angle A and B also equal.

Also cos of any angle equal to the ratio of adjacent to hypotenuse.

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May this will be helpful for you thanks

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Answer 2

Answer:

(￣3￣)(￣3￣)(￣3￣)(￣3￣)(￣3￣)(￣3￣)kissi do