if angle A and angle B are acute angles such that tan A =tan P , then show that angle A = angle P
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In a triangle
Cos A = cos B

AC/AB= BC/AB
⇒AC=BC
⇒Angle A and Angle B
∠A = ∠B
Cos A = cos B

AC/AB= BC/AB
⇒AC=BC
⇒Angle A and Angle B
∠A = ∠B
Answered by
18
Solution : - consider a right traingle ABC having two acute angle
°•° TanA = TanB ( Given)
since , BC / AC= AC /BC
=> BC² = AC²
=> BC = AC
so , TanA = 1 and similarly tanB = 1
And as we know that 1 = tan45°
since, tanA = tan45°
A = 45°
Similarly tanB = tan45°
B = 45°
Hence, A = B
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