If angle A is 3x+4and ANGLE B IS 50+x and angle C is 5x+8 and agle D is 3x+10 then find angle DaB
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Answer:
sum of all angles is 360
3x+4+50+x+5x+8+3x+10 =360
12x+72=360
12x=360-72
12x=288
x=288/12
x=24
so, angle DAB = 3*24+4
72+4
76
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