Question

if angle A mins angle B=40º,angle B mins angle C=10º, angle C mins angle A=30º.Find the angle A, B, C.

Answer 1

GIVEN

A-B =  40 AND B-C = 10 AND C-A = 30

A - B = 40 ==> A = 40+B

B - C = 10

==> -C = 10-B

==> C = -(10-B) ==> -10+B

WE KNOW THAT SOME OF ALL INTERIOR ANGLE IN TRIANGLE IS 180

           A+B+C = 180

SO,  40+B+B-10+B = 180

==> 30+3B = 180

==> 3(10+B) = 180

==> 10+B = 60

==> B = 60-10 ==> 50

A =  40+B = 40+50 ==> 90

SO, A = 90

C = -10+B  = -10+50 ==> 40

SO, A = 90 , B = 50 , C = 40