if angle abc , AB = AC and Angle A is 40 degree find X and Y .
not goögle copied
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Answered by
11
Answer:
In ∆ABC,
If, AB = AC
then, ∠ABC = ∠ACB
So, Let ∠ABC be x.
then, ∠ABC = ∠ACB = x
40° + x° + x° = 180° [∵ angle sum property of a triangle]
40° + 2x° = 180°
2x° = 180° - 40°
2x° = 140°
x° =
x° = 70°
then, ∠ABC = ∠ACB = 70°
180° - 70° = 110°
∴
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Answered by
23
Answer:
- = 180°
- 40° + ∆ABC + ∆ACB = 180°
- 2∆ABC = 180° - 40°
- 2∆ABC = 140°
- ∆ABC = 140/2 = 70°
- ∆ABC + x° = 180°
- 70° + x° = 180°
- x° = 180° - 70°
- x° = 110°
- ∆ABC + y° = 180°
- 70 + y° = 180°
- y° = 180° - 70°
- y° = 110°
hence. x = 110 , y = 110
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