Math, asked by foorquanshaikh07, 6 months ago

if angle ABC; an angle (ACD = 108 them find angle (ACB) =?​

Answers

Answered by anandwag76
0

Answer:

Given = angle ACD =108

To find =angle (ACB) =?

Here, from given condition,

Angle ACD is the exterior angle of Triangle ACB.

therefore, angle A +angle B+angle C=180......(1)

hence, 108 + angle ACD =180.........( by remote interior angles theorem.)

therefore,

angle ACD=72 degree.

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