Question

if angle ABC = angle A + angle C

and AB = BD

then , prove that =>BC = CD


most appropriate and correct answer will get a brainliest

Answer 1

Hey there!!

We have ∆ABD and. ∆BCD

Given -

∠ABC = ∠A+∠C


AB = BD

To prove - BC = CD

Now in ∆ABD and ∆BCD

∠A = ∠A ( ∵ ∠ABC = ∠A + ∠ C)

BD = DA ( Common )

∠D = ∠D ( Common Bisector)

Hence , ∆ABD ≅∆BCD

⇒ BC = CD ( By CPCT)



Hope this would help you !!