Question

if angle ABC ~ angle RSM and if AB = 10 BC = 12 RS = 5
find SM
yall please answer fast nd DONT SPAM B! ILL REPORT YOU!​

Answer 1

$\huge\mathbf{Answer}$

Given

$∆ABC\sim ∆RSM$ ,AB = 10cm, BC = 12cm, RS = 5cm.

To Find:- SM = ?

We know that:

In a pair of similar triangles, the corresponding sides are proportional.

$\dfrac{AB} {RS}\:=\:\dfrac{BC} {SM}\:=\:\dfrac{AC} {RM}$

$\dfrac{10} {5}\:=\:\dfrac{12} {SM}$[Don't take AC and RM sides]

$SM\:=\:\dfrac{12 ×5} {10}$

$SM\:=\:6cm$

Therefore, SM Is 6cm.

Answer 2

Answer:

\huge\mathbf{Answer}Answer

Given

∆ABC\sim ∆RSM∆ABC∼∆RSM ,AB = 10cm, BC = 12cm, RS = 5cm.

To Find:- SM = ?

We know that:

In a pair of similar triangles, the corresponding sides are proportional.

\dfrac{AB} {RS}\:=\:\dfrac{BC} {SM}\:=\:\dfrac{AC} {RM}

RS

AB

=

SM

BC

=

RM

AC

\dfrac{10} {5}\:=\:\dfrac{12} {SM}

5

10

=

SM

12

[Don't take AC and RM sides]

SM\:=\:\dfrac{12 ×5} {10}SM=

10

12×5

SM\:=\:6cmSM=6cm

Therefore, SM Is 6cm.