if angle adb is a right angle, find the value of x.
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As angle ADB = 90 degree (given)
angle DAB = 35 degree (given)
In triangle ADB
angle ABD = 180 - (90 +35) degree (as sum of three angles in triangle is 180 degrees)
angle ABD = 55 degrees
In triangle BCE
angle BCE = 29 degree (given)
angle ABD = EBC = 55 degree (as derived earlier)
Therefore,
angle CEB = 180 - (55 + 29) degree (as sum of three angles in triangle is 180 degrees)
angle CEB = 96 degre
Linear pair (angle AEC + angle BEC = 180 degree)
Therefore, x + 96 = 180
X = 180 - 96 = 84 degree
angle DAB = 35 degree (given)
In triangle ADB
angle ABD = 180 - (90 +35) degree (as sum of three angles in triangle is 180 degrees)
angle ABD = 55 degrees
In triangle BCE
angle BCE = 29 degree (given)
angle ABD = EBC = 55 degree (as derived earlier)
Therefore,
angle CEB = 180 - (55 + 29) degree (as sum of three angles in triangle is 180 degrees)
angle CEB = 96 degre
Linear pair (angle AEC + angle BEC = 180 degree)
Therefore, x + 96 = 180
X = 180 - 96 = 84 degree
shiva198:
wrong answer
Answered by
1
Answer:
friend you have written the 90 degree at wrong place. 90 degree ADB not the place where u have written
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