If angle AOB =125, find angle cod
uv12:
u hv to post the pic of the diagram
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where is the figure ?
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5
Thank you for asking this question. Here is your answer:
The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center.
ABCD will meet at a point where it won't cut it but it will just pass it, and that would be the center at O.
∠AOB + ∠COD = 180°
125° + ∠COD = 180°
∠COD = 180° - 125°
∠COD = 55°
If there is any confusion please leave a comment below.
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