Math, asked by sachinlamba4975, 1 year ago

If angle AOB =125, find angle cod


uv12: u hv to post the pic of the diagram

Answers

Answered by Anonymous
4
where is the figure ?
Answered by Shaizakincsem
5

Thank you for asking this question. Here is your answer:

The quadrilateral angle's circle meet at the point of the supplementary angles and that is at the center.

ABCD will meet at a point where it won't cut it but it will just pass it, and that would be the center at O.

∠AOB + ∠COD = 180°

125° + ∠COD = 180°

∠COD = 180° - 125°

∠COD = 55°

If there is any confusion please leave a comment below.

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