If angle aop =5y,angle qod =2y & angle boc =5y find value of x
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In the figure, POQ is a line, ∠ POR = 4x and ∠ QOR = 2x. Find the value of x.
Solution:
∠ POR + ∠ QOR = 180° (Linear pair axiom)
But ∠ POR = 4x and ∠ QOR = 2x
∴ 4x+2x = 180°
⇒ 6x = 180°
Þ x = 30°
∴ The value of x = 30° .
Solution:
∠ POR + ∠ QOR = 180° (Linear pair axiom)
But ∠ POR = 4x and ∠ QOR = 2x
∴ 4x+2x = 180°
⇒ 6x = 180°
Þ x = 30°
∴ The value of x = 30° .
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