Question

if angle B=2angle C and AD bisects angle BAC and AD=CD. Find angle BAC​

Answer 1

Answer:

Triangle ABC and ADC are similar (two sides and one angle is equal)

So ∠ CAD = ∠ ACB = C

∠BAC = 2c

And in triangle ABC ∠BAC + ∠ABC + ∠ACB

2c+2c+c=180°

5c=180°

c= 180/5

c= 36

∠BAC = 2c

= 2x36

= 72°

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Answer 2

Answer:

answer is here

Step-by-step explanation:

AD= CD

therefore

angle DAC = angle DCA. (1)

angle BAD= angle CAD. (2)

from 1 and 2,

angle BAD= angle DCA

now,

angle ABC + angle BAC + angle BCA= 180°

2 angle C + 2 angle C + angle C = 180°

5 angle C = 180°

angle C = 36°

angle BAC= 36° * 2 = 72°

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