if Angle B = 90 degree of triangle ABC then the value of Sin (A + c) is
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B = 90
A+B+C = 180
A+C = 180-90
A+C = 90
sin90 = 1
A+B+C = 180
A+C = 180-90
A+C = 90
sin90 = 1
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If angle B = 90° of triangle ABC then the value of sin (A + C) is 1
Given : angle B = 90° of triangle ABC
To find : The value of sin (A + C)
Solution :
Step 1 of 2 :
Find A + C
Here it is given that angle B = 90° of triangle ABC
We know that for a triangle sum of three angles = 180°
∴ A + B + C = 180°
⇒ A + 90° + C = 180°
⇒ A + C = 90°
Step 2 of 2 :
Find the value of sin (A + C)
∴ sin (A + C)
= sin 90°
= 1
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