if Angle B and Angle A are acute angles such that cos A is equal to cos B then show that angle is equal to Angle B
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In a triangle
Cos A =cos B
AC/AB= BC/AB
⇒AC=BC
⇒Angle A and Angle B
Cos A =cos B
AC/AB= BC/AB
⇒AC=BC
⇒Angle A and Angle B
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