If Angle B and angle Q are acute angles such that Sin B equal to sin Q then prove that angle b is equal to angle q?
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Consider a ΔABQ having sin B = sin Q .... (1)
Now, in ΔABQ, we have
sin B =AQ/BQand sin Q =AB/BQ
On putting the above values in (1), we get
AQ/BQ=AB/BQ
Therefore, AQ=AB
So, AQ = AB implies that,
∠B = ∠Q [Angles opposite to equal sides are equal.]
REGARDS ...:^:
Now, in ΔABQ, we have
sin B =AQ/BQand sin Q =AB/BQ
On putting the above values in (1), we get
AQ/BQ=AB/BQ
Therefore, AQ=AB
So, AQ = AB implies that,
∠B = ∠Q [Angles opposite to equal sides are equal.]
REGARDS ...:^:
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