Question

If angle B and angle Q are acute angles such that sin B = sin Q, then prove that angle B = angle Q​

Answer 1

Answer:

if u draw a right triangle ABQ ,right angled at A(since B and Q are acute)

then we know

sin B = AB/BQ

sin Q = AQ/ BQ

since it's given that sin B = sin Q

AB/BQ = AQ/BQ

AB = AQ

this makes triangle ABQ an iso. triangle

which makes angle B= angle Q

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Answer 2

Answer:

I'm sure you understand my way