If angle B and angle Q are acute angles such that
sin B = sinQ , then prove that angle B = angle Q
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Answered by
4
Answer:
It is given that sin B=sin Q
Clearly, since B and Q are acute angles ,angle B= angle Q
(As sine of two acute angles will be equal only if they are both equal)
You can prove this also by considering a right triangle ABQ
Since B and Q are acute angles ,angle B is right angle
Then sin Q =AB / AQ
sin B =BQ/ AQ
Now sin B =sin Q implies AB=BQ
This gives angle B = angle Q (ans)
Hope it will help you☺✌
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