If angle bap =60° find angle bca
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Answer:
bca= 30=60/2=90/3=120/4=180/6=210/7
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Answer: 60°
Step-by-step explanation:
The tangent to a circle makes 90° with the radius....So, OAP = 90°
Given, BAP = 60°
Thus, OAB = 90 - 60 = 30°
Also, OAB is an isosceles triangle as two of it's sides are radius which r equal...
Hence, OBA = 30
Sum of all angles in a ∆ is 180
So, BOA = 180 - (30 + 30) = 120.....
Now, BCA = 1/2 of central angle = 60°
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