Question

IF ANGLE BOD=40°,FIND THE MEASURE OF EACH OF THE ANGLES, ANGLE BOC,ANGLE AOC AND ANGLE AOD. ​

Answer 1

Answer:

Step-by-step explanation:

Angle BOC = 180 - 40 = 140 (Supplementary Angles)

Angle AOC = 40 (Vertically Opposite Angles)

Angle AOD = 140 (Vertically Opposite Angles)

Answer 2

$\large{\sf{\fbox{Question→}}}$

In the given figure, two straight lines AB and CD intersect at a point o. If BOD = 40°, find the measure of each of the angles, BOC, AOC and AOD.

$\large{\sf{\fbox{Solution →}}}$

$\longrightarrow$ $\sf{BOC=140,AOC=40,AOD=140}$

$\longrightarrow$ $\sf{AOD=AOC---vertically~opposite~angles!}$

$\longrightarrow$ $\sf{We,~know~that→}$

$\sf{CD~is~a~line!}$

$\longrightarrow$ $\sf{BOC+40°=180°}$

$\longrightarrow$ $\sf{BOC=180°-40°}$

$\longrightarrow$ $\sf{BOC=140°}$

$\longrightarrow$ $\sf{AOD=BOC---vertically~opposite~angles!!}$

$\longrightarrow$ $\sf{.°.AOD=140°!!}$