if angle C =90°,then area of triangle ABC is
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In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In △ACD
AD2=AC2+CD2 .....(1)
In △ACB
AB2−AC2=BC2 .....(2)
As CD=DB=2BC ...... (3)
Substituting (3) in (1)
AD2=AC2+4BC2
4AD2−4AC2=BC2 ....... (4)
Subtracting (2) from (4)
4AD2−4AC2−(AB2−AC2)=BC2−BC2
4AD2−4AC2−AB2+AC2=0
4AD2−3AC2=AB2
Hence proved.
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