If angle of triangle are in Ap the smallest angle is 50° find remaning angle
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Step-by-step explanation:
We know that sum of n terms of an Ap is given as
Sn = n/2 (2a + (n-1)d)
Here n = 3 ( no of angles in a ∆ )
Sn = 180 ( sum of angles of a ∆)
a = 50° ( smallest angle)
Substituting values of Sn, a, n in the formula we get.
180 = 3/2 ( 2×50 + (3-1)d)
180 =3/2 (100+2d)
360 = 300 + 6d
360-300 = 6d
d = 60/6 = 10
Hence three angles are a, a+d, a+2d
= 50°, 60°, 70°
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