if angle pqr =100degree where p,q,and r are points on a circle with centre o find angle opr
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the angle you want should be por
angle 2 pqr=por
(10.8theorm class9)
2×100=por
por=200
angle 2 pqr=por
(10.8theorm class9)
2×100=por
por=200
Answered by
6
Hello mate =_=
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Solution:
P, Q and R are the points on a circle with centre O where ∠PQR=100°
Construction: S is a point on the major arc PR. Join P and S, R and S to form a cyclic quadrilateral.
∠PQR+∠PSR=180°
(Sum of opposite angles of a cyclic quadrilateral is equal to 180°)
⇒100°+∠PSR=180°
⇒∠PSR=180°−100°=80°
Also, ∠POR=2∠PSR
(Angle subtended by an arc at the centre is double the angle subtended by it at the circumference of the circle.)
⇒∠POR=2×80°=160°
In ∆POR, we have
∠POR+∠ORP+∠OPR=180°
But, we have ∠ORP=∠OPR (Angles opposite to the equal sides in a triangle are equal.)
⇒160°+∠OPR+∠OPR=180°
⇒2∠OPR=180°−160°=20°
⇒∠OPR=20/2=10°
hope, this will help you.
Thank you______❤
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