If angleA and angleB are acute angles such that cosA= cosB, then show that angleA = angleB.
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Step-by-step explanation:
In the given question Angle A and Angle B are
acute àngles
Therefore triangle ABC is right angled at C
cos A =cosB. (given)
AC/AB= BC/AB
AC=BC. (AB IS CANCELLED BOTH SIDES)
SINCE THE OPPOSITE SIDES ARE EQUAL THE OPPOSITE ANGLES ARE ALSO EQUAL
THEREFORE,
ANGLE A=ANGLE B
HENCE PROVED
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