If angleABC = ADEF, AB = 5 cm, BC =
6 cm, AC = 7 cm, then the length of EF
is:
a.
1 cm
b. 6 cm
C
7 cm
d. 5 cm
Answers
Answered by
0
Step-by-step explanation:
DEF∼△LMN
So, AB/ED=AC/EF=BC/DF
Consider AB/ED=AC/EF
5/12=7/EF
By cross multiplication,
EF=(7×12)/5
EF=16.8cm
Now, consider AB/ED=BC/DF
5/12=BC/15
BC=(5×15)/12
BC=75/12
BC=6.25.
Answered by
0
Answer:
The length of EF is 8cm because you are counting seraily
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