If angleAOB= 60° then find angleACB where C is a point in circle and AB be arc on circle
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Answer:
Given O is the centre of circle.
∠AOB=60
o
To find : ∠ACB, ∠ADB
∠ACB=
2
1
∠AOB
(Angle subtended by the arcA at centre is twice the angle subtended by the arc on the circle)
∴ ∠ACB=30
o
ACBD is a cyclic quadrilateral
Opposite angles in a cyclic quadrilateral sum 180
o
∠ACBb+∠ADB=180
o
30
o
+∠ADB=180
o
∠ADB=150
o
∠ACB=30
o
∠ADB=150
o
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