If angleB and angleQ are acute angles such that sinB=sinQ then prove that angleB=angleQ
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sinB = sinQ
sin theta = opposite/hypotenuse
opposite base /hypotenuse = opposite Q/hypotenuse
hypotenuse is cutted
i.e, opposite angle B = opposite angle Q
or BC = QC
angle opp to equal side is equal
i.e, angle B = angle C
PLEASE MARK MY ANSWER AS A BRAINLIEST.
sinB = sinQ
sin theta = opposite/hypotenuse
opposite base /hypotenuse = opposite Q/hypotenuse
hypotenuse is cutted
i.e, opposite angle B = opposite angle Q
or BC = QC
angle opp to equal side is equal
i.e, angle B = angle C
PLEASE MARK MY ANSWER AS A BRAINLIEST.
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