Question

If angles A and B of triangle ABC are each 2x+5 and angle C is 3x-5 find angle A

Answer 1

Answer:

∠A=∠B=2X+5

∠C=3X-5

IN ΔABC

∠A+∠B+∠C=180  (ANGLE SUM PROPERTY)

2X+5+2X+5+3X-5=180

7X+5=180

7X=175

X=25

∠A= 2X+5=2(25)+5=50+5=55°

Step-by-step explanation:

Answer 2

Answer:

∠A = ∠B = 55 ,∠C = 70

Step-by-step explanation:

given ∠A = ∠B = 2x + 5 and ∠C = 3x - 5

we know in a triangle, sum of all three sides is 180

⇒ ∠A + ∠B + ∠C = 180

⇒ 2x + 5 + 2x + 5 + 3x - 5 = 180

⇒ 7x + 5 = 180

⇒ 7x = 180 - 5

⇒ x = 175/7

∴ x = 25

∠A = ∠B = 2x + 5 = 2(25) + 5 = 55

∠C = 3x - 5 = 3(25) - 5 = 70

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