If angles A, B C, D of quadrilateral ABCB , taken in order, are in the ratio 3:7:6:4 , then ABCD is
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Given, ratio of angles of quadrilateral ABCD is 3 : 7 : 6 : 4.
Let angles of quadrilateral ABCD be 3x, 7x, 6x and 4x, respectively. We know that, sum of all angles of a quadrilateral is 360°.
3x + 7x + 6x + 4x = 360°
=> 20x = 360°
=> x=360°/20° = 18°
Step-by-step explanation:
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Step-by-step explanation:
Let the angles of the quadrilateral be 3x,7x,6x and 4x.
Then, 3x+7x+6x+4x=360∘
⇒20x=360∘
⇒x=18∘
Therefore, the angles A,B,C and D are respectively
∠A=3×18=54,∠B=7×18=126,∠C=6×18=108,∠D=4×18=72.
which shows that ∠A+∠B=180∘ and ∠C+∠D=180∘ →AD∣∣BC.
Hence ABCD is a trapezium.
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