Question

if angles are in the ratio 1:2:3 then find the ratio of its sides​

Answer 1

Answer:

Let the angles of a triangle are x° ,2x°. 3x°.acordingly:-

x°+2x° +3x°=180°

6x°=180°

or. x=30°

Angles are 30° , 60°. and. 90°.

Let a. , b and c units be the length of the sides of the triangle. Applying

sine rule

a/sin30° = b /sin60° = c/sin90°

2.a/1= 2b/√3. = c/1

a= c/2 , b= (c.√3)/2.

a : b : c = c/2. : c√3/2. : c. = 1/2. : √3/2 : 1. or 1 : √3. : 2. Answer.