If angles of a quadrilateral are (2x+10),(x+20),(X+30) and (x-10) then find x
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2x+10+x+20+x+30+x-10=360°
5x+60-10=360
5x+50=360
5x=360-50
5x=310
x=310/5
x=62°
5x+60-10=360
5x+50=360
5x=360-50
5x=310
x=310/5
x=62°
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