If angles of a quadrilateral are (x+10°), (x+30°),(2x -20°),(2x -50°) find the angles of quadrilaterals
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The given angles of a quadrilateral arex
0
,(x−10)
0
,(x+30)
0
and 2x
0
.
We know, that sum of four interior angles of a quadrilateral is 360
o
∴ x+(x−10)+(x+30)+2x=360
o
⇒ 5x+20=360
o
⇒ 5x=340
o
⇒ x=
5
340
o
⇒ x=68
o
Now, measure of an angles,
⇒ x
o
=68
o
⇒ (x−10)
o
=(68−10)
o
=58
o
⇒ (x+30)
o
=(68+30)
o
=98
o
⇒ 2x
o
=2(68
o
)=136
o
∴ The greatest angle is 136
o
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