If angles of a quadrilateral are x-15 , x, x+20 and 2x+5 then find the angles of the parrallelogram
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GIVEN :
=> ANGLES OF A QUADRILATERAL :
=> ( X - 15 )°
=> ( X ) °
=> ( X+ 20 ) °
=> ( 2X+ 5 ) °
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=> SUM OF MEASURES OF ALL ANGLES OF A QUADRILATERAL :
=> 360°
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=> ( X - 15 ) ° + X ° + ( X + 20 ) ° + ( 2X + 5 ) ° = 360°
=> 5 X - 15 + 20 + 5 = 360°
=> 5X + 10 = 360°
=> 5X = 360 ° - 10 °
=> 5X = 350°
=> X = ( 350 / 5 )°
=> X = 70°
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1ST ANGLE :
=> ( X - 15 )°
=> ( 70 - 15 ) °
=> 55°
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SECOND ANGLE :
=> X°
=> 70°
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THIRD ANGLE :
=> ( X + 20 )°
=> ( 70 + 20 ) °
=> 90°
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4TH ANGLE :
=> ( 2X + 5 ) °
=> ( 2* 70 + 5 ) °
=> 140 + 5
=> 145°
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MEASURE OF ALL THE ANGLES OF THE PARALLELOGRAM ARE :
1. => 55°
2. => 70°
3. => 90°
4. => 145°
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HOPE IT WILL HELP U.....
THANKS AGAIN.....
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⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
GIVEN :
=> ANGLES OF A QUADRILATERAL :
=> ( X - 15 )°
=> ( X ) °
=> ( X+ 20 ) °
=> ( 2X+ 5 ) °
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=> SUM OF MEASURES OF ALL ANGLES OF A QUADRILATERAL :
=> 360°
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=> ( X - 15 ) ° + X ° + ( X + 20 ) ° + ( 2X + 5 ) ° = 360°
=> 5 X - 15 + 20 + 5 = 360°
=> 5X + 10 = 360°
=> 5X = 360 ° - 10 °
=> 5X = 350°
=> X = ( 350 / 5 )°
=> X = 70°
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1ST ANGLE :
=> ( X - 15 )°
=> ( 70 - 15 ) °
=> 55°
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SECOND ANGLE :
=> X°
=> 70°
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THIRD ANGLE :
=> ( X + 20 )°
=> ( 70 + 20 ) °
=> 90°
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4TH ANGLE :
=> ( 2X + 5 ) °
=> ( 2* 70 + 5 ) °
=> 140 + 5
=> 145°
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MEASURE OF ALL THE ANGLES OF THE PARALLELOGRAM ARE :
1. => 55°
2. => 70°
3. => 90°
4. => 145°
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HOPE IT WILL HELP U.....
THANKS AGAIN.....
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