Question

if angles of a quadrilatral are x,x+3,x+8,x+9 then find the measure of each angles of the quadrilatral
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Answer 1

Answer:

x + x+3 ×+8 x+9=360

4× + 20=360

4×=360-20

4× = 340

x =340/4

×=85

85,88,90, 94 r the measures of angles

Answer 2

Given:

• $\red{\textrm{Angles of Quadrilateral x, x+3, x+8,x+9}}$

Find:

• $\red{\textrm{Measures of all Angles}}$

Solution:

☯Sum of All angles in Quadrilateral is 360°☯

⤑$\rm{x+x+3+x+8+x+9 = {360}^{\circ}}$

⤑$\rm{4x+3+8+9 = 360}$

⤑$\rm{4x+20 = 360}$

⤑$\rm{4x = 360-20}$

⤑$\rm{4x = 340}$

⤑$\rm{x = \dfrac{340}{4}}$

⤑$\rm{x = 85}$

$\rm{\therefore x = {40}^{\circ}}$

_____________________

⇒$\rm{F1st \: angle = x ={85}^{\circ}}$

⇒$\rm{2nd\:angle = x+3 ={85}^{\circ}+3 = {88}^{\circ}}$

⇒$\rm{3rd \: angle = x+8={85}^{\circ}+ 8= {93}^{\circ}}$

⇒$\rm{4th \: angle = x+9 ={85}^{\circ}+9 = {94}^{\circ}}$