If angles of a triangle are (3y-5)°,(2y+55)° and(5y-50)°, then find the value of Y
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(3y-5)+(2y+55)+(5y-50)=180
3y-5+2y+55+5y-50=180
10y-0=180
10y=180
y=180÷10
y=18
3y-5+2y+55+5y-50=180
10y-0=180
10y=180
y=180÷10
y=18
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