If angles of a triangle are (3y-5)^0 , (2y+55)^0 and (5y-50)^0 , then find value of y
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Answer:
Step-by-step explanation:
Sum of the three angles of a triangle is 180°
(3y-5)°+(2y+55)°+(5y-50)°=180°
10y-5+55-50=180°
10y=180°
Y=180/10
Y=18°
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