Question

If angles of a triangle are in the
ratio 2 3 4 Find the value of each
angle . if the smallest angle is x%
of the greatest angle, find x​

Answer 1

Answer:

${ \bold{ \huge{ \underline{ \: question}}}}$

▪ iF angles of a triangle are in the ratio 2:3:4. Find the value of each angle. If the smallest angle is x% of the greatest angle, find x.

${ \bold{ \huge{ \underline{ \: solution}}}}$

Let the angles of the triangle be 2a, 3a, and 4a respectively.

we know that,

☆For a triangle,

sum of all the three angles = 180°

therefore,

2a + 3a + 4a = 180°

=》 9a = 180 °

=》 a = 20°

the angles of the triangle are-

• 2a = 2×20° = 40°

• 3a = 3×20° = 60°

• 4a = 4× 20° = 80°

the smallest angle = 40°

The greatest angle = 80°

according to the question,

the smallest angle is x% of the greatest angle.

=》 x % = (40/80) ×100

=》 x = 50

hence,

the smallest angle is 50% of the greatest angle.

☆ HoPE iT hELpS you

Answer 2

Solution:-

Let the angle of ratio be x respectively.

2x + 3x + 4x = 180

➡9x = 180

➡x = 20

Therefore, angles = 40°, 60°, 120°

➡x = 40°×100÷120

➡x = 33 (1/3)%

Hence the value of x is 33 (1/3)%.

Hope this is helpful for you.