If angles of ∆ABC are in A. P and b:c=√3:√2 . Find the A°, B° and C°
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Let angle A,B and C be a,a+d,a-d
A/q. a+d+a+a-d=180
3a=180
a=60
B:C=√3:√2
b^2:c^2=3:2
[(60+d)/(60-d)]^2=3/2
2(3600+d^2+120d)=3(3600+d^2-120d)
7200+2d^2+240d=10800+3d^2-360d
360d=d^2+3600
d^2-360d+3600=0
Solve the quadratic formula and find value.
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