Question

if angles of quadrilateral are in A.P and A¹=a , A² = 80° , A³= a+2d , A⁴=120 find A¹ and A³.​

Answer 1

Answer:

$A_{1} =60 ;\\A_{3} =100$

Step-by-step explanation:

$A_{4}-A_{2}$ = a+3d-a-d

     40 = 2d

       d = 20

a + d =80

a = 80 - 20

$A_{1}$ = a = 60

$A_{3}$ = a + 2d = 100

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